document.write( "Question 505669: Pure acid is to be added to a 5% acid solution to obtain 95L of 30% solution. What amounts of each should be used?
\n" ); document.write( " How many Liters of 100% acid should be used to obtain the solution? \n" ); document.write( "
Algebra.Com's Answer #339928 by stanbon(75887)\"\" \"About 
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Pure acid is to be added to a 5% acid solution to obtain 95L of 30% solution. What amounts of each should be used?
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.05x + 1.0(95-x) = 0.30*95
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\n" ); document.write( "Multiply thr by 100 to get:
\n" ); document.write( "5x + 100*95 - 100x = 30*95
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\n" ); document.write( "-95x = -70*95
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\n" ); document.write( "x = 70L (amt of 5% solution needed)
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\n" ); document.write( "95-x = 25L (amt of 100% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "\n" ); document.write( "How many Liters of 100% acid should be used to obtain the solution?
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