document.write( "Question 505553: In a single spin, what is the probability of obtaining a C given the spinner did not land on a B?
\n" ); document.write( "P(A): 2/5
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Algebra.Com's Answer #339917 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The other tutor misunderstood that A,B,C, and D are the\r\n" );
document.write( "letters on the spinner.\r\n" );
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document.write( "The conditional probability of X given Y is given by the formula:\r\n" );
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document.write( "          P(X and Y)\r\n" );
document.write( "P(X|Y) = ------------\r\n" );
document.write( "             P(Y) \r\n" );
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document.write( "              P(C and not B)\r\n" );
document.write( "P(C|not B) = --------------- \r\n" );
document.write( "                P(not B)\r\n" );
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document.write( "P(C and not B) = P(C) = \"1%2F10\"\r\n" );
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document.write( "P(not B) = 1 - P(B) = 1 - \"1%2F5\" = \"5%2F5\" - \"1%2F5\" = \"4%2F5\"\r\n" );
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document.write( "              P(C and not B)      \"1%2F10\"\r\n" );
document.write( "P(C|not B) = --------------- =  -------- =  \"1%2F10\"\"%22%F7%22\"\"4%2F5\" = \"1%2F10\"\"%22%22%2A%22%22\"\"5%2F4\" = \"1%2F8\"\r\n" );
document.write( "                P(not B)           \"4%2F5\"\r\n" );
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document.write( "Edwin
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