document.write( "Question 505535: -2/5(10j-15)=20 \n" ); document.write( "
Algebra.Com's Answer #339909 by stanbon(75887)\"\" \"About 
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-2/5(10j-15)=20
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\n" ); document.write( "Multiply both sides by 5 to get:
\n" ); document.write( "-2(10j-15) = 100
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\n" ); document.write( "Divide by -2 to get:
\n" ); document.write( "10j - 15 = -50
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\n" ); document.write( "10j = -35
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\n" ); document.write( "Divide by 10 to get:
\n" ); document.write( "j = -3/2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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