document.write( "Question 505488: Six hundred pennies are placed in a row. If every other penny is replaced by a nickel and every third coin is replaced by a quarter, what is the final value of the 600 coins?
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Algebra.Com's Answer #339906 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We only need to look at the first 6 coins and multiply their\r\n" );
document.write( "value by 100, because each of the 100 groups of 6 turn out\r\n" );
document.write( "the same way.\r\n" );
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document.write( "We start with\r\n" );
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document.write( "1¢ + 1¢ +  1¢ + 1¢ + 1¢ +  1¢  + ···\r\n" );
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document.write( "Then we replace every other one with a nickel and have this:\r\n" );
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document.write( "1¢ + 5¢ +  1¢ + 5¢ + 1¢ +  5¢  + ···\r\n" );
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document.write( "Then we replace every 3rd one with a quarter and have this:\r\n" );
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document.write( "1¢ + 5¢ + 25¢ + 5¢ + 1¢ + 25¢  + ···\r\n" );
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document.write( "That last line adds to 62¢ and we\r\n" );
document.write( "have 100 groups just like this one,\r\n" );
document.write( "so the total amount of money is $62.\r\n" );
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document.write( "Edwin
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