document.write( "Question 505410: I really need help with this and need this word problem translated into an algebraic equation with only one variable. Then it needs to be simplified.
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document.write( "The area of a rectangle is 72 square inches. If the length is 40 inches greater than four times the width, what are the dimensions of the rectangle? \n" );
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Algebra.Com's Answer #339890 by Taxie(4)![]() ![]() ![]() You can put this solution on YOUR website! call the width w. The length is then 4w+40 \n" ); document.write( "The area of the rectangle is then. 72 = 4w + 40 \n" ); document.write( "Simplify dividing the equation by 4 to get. 18 = w + 10 \n" ); document.write( "The solution is w = 8\r \n" ); document.write( "\n" ); document.write( "(sorry I misread 4 for 40 in th previous post)\r \n" ); document.write( "\n" ); document.write( "Ciao \n" ); document.write( " |