document.write( "Question 505410: I really need help with this and need this word problem translated into an algebraic equation with only one variable. Then it needs to be simplified.
\n" ); document.write( "Question:
\n" ); document.write( "The area of a rectangle is 72 square inches. If the length is 40 inches greater than four times the width, what are the dimensions of the rectangle?
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Algebra.Com's Answer #339890 by Taxie(4)\"\" \"About 
You can put this solution on YOUR website!
call the width w. The length is then 4w+40
\n" ); document.write( "The area of the rectangle is then. 72 = 4w + 40
\n" ); document.write( "Simplify dividing the equation by 4 to get. 18 = w + 10
\n" ); document.write( "The solution is w = 8\r
\n" ); document.write( "\n" ); document.write( "(sorry I misread 4 for 40 in th previous post)\r
\n" ); document.write( "\n" ); document.write( "Ciao
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