document.write( "Question 505410: I really need help with this and need this word problem translated into an algebraic equation with only one variable. Then it needs to be simplified.
\n" ); document.write( "Question:
\n" ); document.write( "The area of a rectangle is 72 square inches. If the length is 40 inches greater than four times the width, what are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #339889 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The area of a rectangle is 72 square inches.
\n" ); document.write( "L * W = 72 sq/in
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\n" ); document.write( " If the length is 40 inches greater than four times the width,
\n" ); document.write( "L = 4W+40
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\n" ); document.write( "In the 1st equation, replace L with (4W+40)
\n" ); document.write( "(4W+40) * W = 72
\n" ); document.write( "4W^2 + 40W = 72
\n" ); document.write( "Simplify, divide by 4
\n" ); document.write( "W^2 + 10W = 18
\n" ); document.write( "A quadratic equation
\n" ); document.write( "W^2 + 10W - 18 = 0
\n" ); document.write( "Won't factor, have to solve it with the quadratic formula
\n" ); document.write( "a=1; b=10; c= -18
\n" ); document.write( "The positive solution = 1.55743852\" is the width of the rectangle
\n" ); document.write( "then
\n" ); document.write( "4(1.55743852) + 40 = 46.22975408\" is the length
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\n" ); document.write( "Confirm this by finding the area using these two dimensions\r
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