document.write( "Question 505293: Solve by factoring (please show work)\r
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document.write( "and\r
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document.write( "If you can help with both that would be much appreciated, but if you can only solve one i understand. \n" );
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Algebra.Com's Answer #339846 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x^2+5x+6=0 \n" ); document.write( "x^2+3x+2x+6=0 \n" ); document.write( "x(x+3)+2(x+3)=0 \n" ); document.write( "(x+2)(x+3)=0 \n" ); document.write( "x+2=0 or x+3=0 \n" ); document.write( "x=-2 or x=-3 \n" ); document.write( "Check \n" ); document.write( "Put x=-2 in original equation \n" ); document.write( "x^2+5x+6=0 \n" ); document.write( "(-2)^2+5(-2)+6=0 \n" ); document.write( "4-10+6=0 \n" ); document.write( "-6+6=0 \n" ); document.write( "0=0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x^2-x-3=0 \n" ); document.write( "2x^2-3x+2x-3=0 \n" ); document.write( "x(2x-3)+1(2x-3) \n" ); document.write( "(2x-3)(x+1)=0 \n" ); document.write( "2x-3=0 or x+1=0 \n" ); document.write( "2x=3 or x=-10 \n" ); document.write( "x=3/2 or x=-1\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "2x^2-x-3=0 \n" ); document.write( "Put x=3/2 in original equation \n" ); document.write( "2(3/2)^2-(3/2)-3=0 \n" ); document.write( "2(9/4)-(3/2)-3=0 \n" ); document.write( "(9/2)-(3/2)-3=0 \n" ); document.write( "Multiply by 2 both sides of above equation \n" ); document.write( "2*(9/2)-2*(3/2)-2*3=0 \n" ); document.write( "9-3-6=0 \n" ); document.write( "6-6=0 \n" ); document.write( "0=0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |