document.write( "Question 505204: \"How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? With complete solution\" \n" ); document.write( "
Algebra.Com's Answer #339814 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! \"How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? With complete solution\" \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.40x + 0.65(20-x) = 0.50*20 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "40x + 65*20 - 65x = 40*20 \n" ); document.write( "-25x = -15*20 \n" ); document.write( "x = 12 liters (amt. of 40% solution needed) \n" ); document.write( "20-x = 8 liters (amt. of 65% solution needed) \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=== \n" ); document.write( " |