document.write( "Question 505204: \"How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? With complete solution\" \n" ); document.write( "
Algebra.Com's Answer #339814 by stanbon(75887)\"\" \"About 
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\"How many liters of a 40% alcohol solution must be mixed with a 65% solution to obtain 20 liters of a 50% solution? With complete solution\"
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
\n" ); document.write( "0.40x + 0.65(20-x) = 0.50*20
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "40x + 65*20 - 65x = 40*20
\n" ); document.write( "-25x = -15*20
\n" ); document.write( "x = 12 liters (amt. of 40% solution needed)
\n" ); document.write( "20-x = 8 liters (amt. of 65% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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