document.write( "Question 505195: The perimeter of a rectangular painting is 290 centimeters. If the length of the painting is 94 centimeters, what is its width? \n" ); document.write( "
Algebra.Com's Answer #339812 by geetha_rama(94)![]() ![]() ![]() You can put this solution on YOUR website! Perimerer of rectangle = 2(l+w)\r \n" ); document.write( "\n" ); document.write( "2*(l+w) = 290 cms \n" ); document.write( "length = 94cms \n" ); document.write( "2*(94+w) = 290 \n" ); document.write( "w+94 = 145 \n" ); document.write( "w = 145 -94 \n" ); document.write( " = 51 cms\r \n" ); document.write( "\n" ); document.write( "Width of the rectangle is 51 cms \n" ); document.write( " |