document.write( "Question 505195: The perimeter of a rectangular painting is 290 centimeters. If the length of the painting is 94 centimeters, what is its width? \n" ); document.write( "
Algebra.Com's Answer #339812 by geetha_rama(94)\"\" \"About 
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Perimerer of rectangle = 2(l+w)\r
\n" ); document.write( "\n" ); document.write( "2*(l+w) = 290 cms
\n" ); document.write( "length = 94cms
\n" ); document.write( "2*(94+w) = 290
\n" ); document.write( "w+94 = 145
\n" ); document.write( "w = 145 -94
\n" ); document.write( " = 51 cms\r
\n" ); document.write( "\n" ); document.write( "Width of the rectangle is 51 cms
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