document.write( "Question 505177: Equal amounts are invested in each of the three accounts paying 7%, 8% and 10.5% annually. If one year's combined interest income is $1249.50, how much is invested in each amount? \n" ); document.write( "
Algebra.Com's Answer #339805 by geetha_rama(94)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the amount invested in each of the three accounts \n" ); document.write( "Interest earned in account paying 7% interest I1 = 7x/100 \n" ); document.write( "Interest earned in account paying 8% interest I2 = 8x/100 \n" ); document.write( "Interest earned in account paying 10.5% interest I3 = 10.5x/100\r \n" ); document.write( "\n" ); document.write( "Total Interest = 1249.50 \n" ); document.write( "I1 + I2 +I3 = 1249.50 \n" ); document.write( "7x/100 + 8x/100 + 10.5/100 = 1249.50\r \n" ); document.write( "\n" ); document.write( "=> 7x + 8x + 10.5x = 124950 \n" ); document.write( "=>25.5x = 124950\r \n" ); document.write( "\n" ); document.write( "x = 4900\r \n" ); document.write( "\n" ); document.write( "Amount investeed in each of the account is $4900 \n" ); document.write( " |