document.write( "Question 505155: The length of a rectangle is twice the width. The perimeter is 48 in. Find the dimensions of the rectangle.\r
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Algebra.Com's Answer #339792 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Length = l = 2w
\n" ); document.write( "width = w
\n" ); document.write( "Perimeter = P = 48\r
\n" ); document.write( "\n" ); document.write( "P = 2l + 2w
\n" ); document.write( "Given l=2w
\n" ); document.write( "48=2(2w) + 2w
\n" ); document.write( "48=4w + 2w
\n" ); document.write( "48=6w
\n" ); document.write( "Divide by 6 both sides of above equation
\n" ); document.write( "48/6=6w/6
\n" ); document.write( "8=w
\n" ); document.write( "w=8\r
\n" ); document.write( "\n" ); document.write( "Dimensions of rectangle\r
\n" ); document.write( "\n" ); document.write( "Length = l = 2w = 2 (8) = 16
\n" ); document.write( "width = w = 8
\n" ); document.write( "Perimeter = P = 48\r
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