document.write( "Question 505087: an auto mechanic needs 24 gallons of ani-freeze with a 30 percent glycol concentration. he has on hand only anit-freeze with a 40 percent glycol concentration and one with a 10 percent glycol concentration. How much of the 40 percent should he mix with the 10 percent to get the 24 gallons of 30 percent solution he needs? \n" ); document.write( "

Algebra.Com's Answer #339777 by Earlsdon(6294) $\"\"$ $\"About$

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Let x = the required number of gallons of the 40% glycol solution. This is to be added to (24-x) gallons of the 10% glycol solution to obtain 24 gallons of 30% glycol solution. The equation to solve for x is:
\n" ); document.write( "0.4x+0.1(24-x) = 0.3(24)
\n" ); document.write( "0.4x+2.4-0.1x = 7.2 Simplify.
\n" ); document.write( "0.3x+2.4 = 7.2
\n" ); document.write( "0.3x = 4.8
\n" ); document.write( "x = 16 gallons and (24-x) = 8 gallons.
\n" ); document.write( "The mechanic will need to mix 16 gallons of the 40% glycol solution with 8 gallons of the 10% glycol solution to obtain 24 gallons of 30% glycol solution. \n" ); document.write( "

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