document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=504877>Question 504877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi<BR>\n" );
document.write( "i hope i chose the correct word problem grouping\r<BR>\n" );
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document.write( "from a  puzzle paperback\r<BR>\n" );
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document.write( "a + b + c + d = 15<BR>\n" );
document.write( "further<BR>\n" );
document.write( "b + c = 6<BR>\n" );
document.write( "c + d = 7\r<BR>\n" );
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document.write( "all integers >= 1 and no integers are the same value\r<BR>\n" );
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document.write( "i tried getting a,b, and d in terms of c\r<BR>\n" );
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document.write( "b = 6 - c<BR>\n" );
document.write( "d = 7 - c<BR>\n" );
document.write( "even <BR>\n" );
document.write( "a = c + 2 ?\r<BR>\n" );
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document.write( "but my logic circuit fails ...\r<BR>\n" );
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document.write( "any lighthouse beam offered to steer my toward the answer<BR>\n" );
document.write( "appreciated<BR>\n" );
document.write( "as i am adrift and quite stymied\r<BR>\n" );
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document.write( "thank you<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339723 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Guess and check is probably the best method here. We know that b cannot be 3, otherwise c would be 3 and we want all integers to be different. If b = 2, then c = 4, d = 3, and a = 6. Or, if b = 4, then c = 3, a = 8, etc. If your equation \"a = c+2\" is a given condition, then I would go with the first solution (a,b,c,d) = (6,2,4,3). </SPAN>\n" );
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