document.write( "Question 504657: what value of x satisfies the given conditions: y1=10(2x-1),y2=2x+1, and y1 is 14 more than 8 times y2. \n" ); document.write( "

Algebra.Com's Answer #339696 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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what value of x satisfies the given conditions: y1=10(2x-1),y2=2x+1, and y1 is 14 more than 8 times y2.
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\n" ); document.write( "Three equations
\n" ); document.write( "y1 = 10(2x-1)
\n" ); document.write( "y1 = 20x - 10
\n" ); document.write( "and
\n" ); document.write( "y2 = 2x + 1
\n" ); document.write( "and
\n" ); document.write( "y1 = 8(y2) + 14
\n" ); document.write( "Find y1 in terms of x, replace y2 with (2x+1)
\n" ); document.write( "y1 = 8(2x+1) + 14
\n" ); document.write( "y1 = 16x + 8 + 14
\n" ); document.write( "y1 = 16x + 22
\n" ); document.write( ":
\n" ); document.write( "Back to the 1st equation, replace y1 with (16x+22)
\n" ); document.write( "16x + 22 = 20x - 10
\n" ); document.write( "22 + 10 = 20x - 16x
\n" ); document.write( "32 = 4x
\n" ); document.write( "x = $\"32%2F4\"$
\n" ); document.write( "x = 8 satisfies the equations
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this solution, find y2
\n" ); document.write( "y2 = 2x + 1
\n" ); document.write( "y2 = 2(8) + 1
\n" ); document.write( "y2 = 17
\n" ); document.write( "and y1
\n" ); document.write( "y1 = 20x -10
\n" ); document.write( "y1 = 20(8) - 10
\n" ); document.write( "y1 = 150
\n" ); document.write( ":
\n" ); document.write( "Check for equality in the equation: y1 = 8(y2) + 14
\n" ); document.write( "150 = 8(17) + 14
\n" ); document.write( "150 = 136 + 14; confirms our solution of x=8 \n" ); document.write( "

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