document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=504724>Question 504724</A>: <I><SPAN STYLE=\"word-break: break-all;\"> True or false; 3/3+sqrt of 3. the numerator and the denominator must be multiplied by the square root of 3 to rationalize? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339688 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339688\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> True or false; <BR>\n" );
document.write( "3/(3+sqrt(3))<BR>\n" );
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document.write( " the numerator and the denominator must be multiplied by the square root of 3 to rationalize?<BR>\n" );
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document.write( "Ans: False:::<BR>\n" );
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document.write( "Why?::The numerator and denominator must<BR>\n" );
document.write( "be multiplied by (3-sqrt(3))<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H<BR>\n" );
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