document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=503881>Question 503881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation of a circle with endpoints of the diameter at (-3, -7) and (14, 22) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339686 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write an equation of a circle with endpoints of the diameter at (-3, -7) and (14, 22)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Standard form of equation for circle: (x-h)^2+(y-k)^2=r^2, with (h,k) being the (x,y) coordinates or the center, r=radius<BR>\n" );
document.write( "Using midpoint formula to find center of circle:<BR>\n" );
document.write( "(x1+x2)/2, (y1+y2)/2<BR>\n" );
document.write( "=(14-3)/2, (22-7)/2<BR>\n" );
document.write( "=11/2,15/2<BR>\n" );
document.write( "center(11/2,15/2)<BR>\n" );
document.write( "Use distance formula to find radius of circle (between center and one of given endpoint (-3,-7)<BR>\n" );
document.write( "r^2=(x1-x2)^2+(y1-y2)^2<BR>\n" );
document.write( "=(-3-11/2)^2+(-7-15/2)^2<BR>\n" );
document.write( "=72.25+210.25<BR>\n" );
document.write( "=282.5<BR>\n" );
document.write( "Equation of circle:<BR>\n" );
document.write( "(x-11/2)^2+(y-15/2)^2=282.5 </SPAN>\n" );
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