document.write( "Question 504671: The length of the rectangle is 3 centimeters greater than the width. If the perimeter equals 54 centimeters, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #339677 by Maths68(1474)\"\" \"About 
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The length of the rectangle is 3 centimeters greater than the width
\n" ); document.write( "l = w + 3 ........(1)\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2l + 2w
\n" ); document.write( "54=2l+2w
\n" ); document.write( "Put the value of l in above equation
\n" ); document.write( "54=2(w+3)+2w
\n" ); document.write( "54=2w+6+2w
\n" ); document.write( "54=4w+6
\n" ); document.write( "54-6=4w
\n" ); document.write( "48=4w
\n" ); document.write( "Divide by 4 both sides of above equation
\n" ); document.write( "48/4=4w/4
\n" ); document.write( "12=w
\n" ); document.write( "w=12
\n" ); document.write( "Put the value of w in (1)
\n" ); document.write( "l = w + 3
\n" ); document.write( "l = 12 + 3
\n" ); document.write( "l = 15
\n" ); document.write( "Dimensions of rectangle
\n" ); document.write( "Length = 15 cm
\n" ); document.write( "Width = 12 cm
\n" ); document.write( "Perimeter = 54 cm\r
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