document.write( "Question 504644: hi im 40 and in algebra at my college and im stuck please help!!!\r
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document.write( "(2/5)^2*3/8+1/5 divided by 3/4 \n" );
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Algebra.Com's Answer #339672 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! (2/5)^2*3/8+1/5 divided by 3/4 \n" ); document.write( "Use BODMAS rule \n" ); document.write( "First solve Brackets \n" ); document.write( "then Order (powers etc.) \n" ); document.write( "then Divide \n" ); document.write( "then Multiply \n" ); document.write( "then Add \n" ); document.write( "then Subtract\r \n" ); document.write( "\n" ); document.write( "here we go \n" ); document.write( "=[(2/5)^2*3/8+1/5]/3/4 \n" ); document.write( "=[(4/25)*3/8 + 1/5]/3/4 \n" ); document.write( "=[(4*3/25*8)+1/5]/3/4 \n" ); document.write( "=[12/200+1/5]/3/4 \n" ); document.write( "=[3/50+1/5]/3/4 \n" ); document.write( "Taking LCM \n" ); document.write( "=[(3+10)/50]/3/4 \n" ); document.write( "=(13/50)/3/4 (inverse 3/4 and change the divide sign to multiply) \n" ); document.write( "=(13/50) * 4/3 \n" ); document.write( "=(13*4) / (50 * 3) \n" ); document.write( "=(13*2) / (25 * 3) \n" ); document.write( "=26/75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |