document.write( "Question 504644: hi im 40 and in algebra at my college and im stuck please help!!!\r
\n" ); document.write( "\n" ); document.write( "(2/5)^2*3/8+1/5 divided by 3/4
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Algebra.Com's Answer #339672 by Maths68(1474)\"\" \"About 
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(2/5)^2*3/8+1/5 divided by 3/4
\n" ); document.write( "Use BODMAS rule
\n" ); document.write( "First solve Brackets
\n" ); document.write( "then Order (powers etc.)
\n" ); document.write( "then Divide
\n" ); document.write( "then Multiply
\n" ); document.write( "then Add
\n" ); document.write( "then Subtract\r
\n" ); document.write( "\n" ); document.write( "here we go
\n" ); document.write( "=[(2/5)^2*3/8+1/5]/3/4
\n" ); document.write( "=[(4/25)*3/8 + 1/5]/3/4
\n" ); document.write( "=[(4*3/25*8)+1/5]/3/4
\n" ); document.write( "=[12/200+1/5]/3/4
\n" ); document.write( "=[3/50+1/5]/3/4
\n" ); document.write( "Taking LCM
\n" ); document.write( "=[(3+10)/50]/3/4
\n" ); document.write( "=(13/50)/3/4 (inverse 3/4 and change the divide sign to multiply)
\n" ); document.write( "=(13/50) * 4/3
\n" ); document.write( "=(13*4) / (50 * 3)
\n" ); document.write( "=(13*2) / (25 * 3)
\n" ); document.write( "=26/75\r
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\n" ); document.write( "\n" ); document.write( "= \r
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