document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=504607>Question 504607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the right triangle give the length not given. Give an exact answer and an approximation to three decimal places. \r<BR>\n" );
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document.write( "a=11<BR>\n" );
document.write( "b=11<BR>\n" );
document.write( "c?\r<BR>\n" );
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document.write( "This is what I got so far:\r<BR>\n" );
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document.write( "11^2+11^2=c^2=<BR>\n" );
document.write( "121+121=c^2=<BR>\n" );
document.write( "242=c^2=<BR>\n" );
document.write( "c sqrt242=<BR>\n" );
document.write( "11 sqrt2\r<BR>\n" );
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document.write( "I checked this and it is correct so far according to the mathlab. The problem I am having is figuring out how to get an approximate value to three decimal points. It says to use a calculator to get the answer but I have no clue how to do it. Can someone please help me???? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339664 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Type either sqrt(242) or 11*sqrt(2) into the calculator to get 15.556 </SPAN>\n" );
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