document.write( "Question 504150: the ages of three children in a family can be expressed as consecutive integers. the square of the age of the youngest child is 4 more than 8 times the age of the oldest. find the ages of the three children \n" ); document.write( "
Algebra.Com's Answer #339660 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of youngest = x \n" ); document.write( "Present age of older = x+1 \n" ); document.write( "Present age of older = x+2\r \n" ); document.write( "\n" ); document.write( "x^2=8(x+2)+4 \n" ); document.write( "x^2=8x+16+4 \n" ); document.write( "x^2-8x=20 \n" ); document.write( "x^2-8x-20=0 \n" ); document.write( "x^2-10x+2x-20=0 \n" ); document.write( "x(x-10)+2(x-10)=0 \n" ); document.write( "(x-10)(x+2)=0 \n" ); document.write( "x-10=0 or x+2=0 \n" ); document.write( "x=10 or x=-2 (Impossible)\r \n" ); document.write( "\n" ); document.write( "So x=10\r \n" ); document.write( "\n" ); document.write( "Present age of youngest = x = 10 \n" ); document.write( "Present age of older = x+1 = 10+1 = 11 \n" ); document.write( "Present age of older = x+2 = 10+2 = 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |