document.write( "Question 504150: the ages of three children in a family can be expressed as consecutive integers. the square of the age of the youngest child is 4 more than 8 times the age of the oldest. find the ages of the three children \n" ); document.write( "
Algebra.Com's Answer #339660 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of youngest = x
\n" ); document.write( "Present age of older = x+1
\n" ); document.write( "Present age of older = x+2\r
\n" ); document.write( "\n" ); document.write( "x^2=8(x+2)+4
\n" ); document.write( "x^2=8x+16+4
\n" ); document.write( "x^2-8x=20
\n" ); document.write( "x^2-8x-20=0
\n" ); document.write( "x^2-10x+2x-20=0
\n" ); document.write( "x(x-10)+2(x-10)=0
\n" ); document.write( "(x-10)(x+2)=0
\n" ); document.write( "x-10=0 or x+2=0
\n" ); document.write( "x=10 or x=-2 (Impossible)\r
\n" ); document.write( "\n" ); document.write( "So x=10\r
\n" ); document.write( "\n" ); document.write( "Present age of youngest = x = 10
\n" ); document.write( "Present age of older = x+1 = 10+1 = 11
\n" ); document.write( "Present age of older = x+2 = 10+2 = 12\r
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