document.write( "Question 504539: A Scientist has one solution that is 10% iodine and another that is 40% iodine. How much of each should the scientist use to produce 100mL of a mixture that is 25% iodine. \n" ); document.write( "
Algebra.Com's Answer #339627 by checkley77(12844)\"\" \"About 
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.10x*.40(100-x)=.25*100
\n" ); document.write( ".10x+40-.40x=25
\n" ); document.write( "-.30x=25-40
\n" ); document.write( "-.30x=-15
\n" ); document.write( "x=-15/-.30
\n" ); document.write( "x=50 ml. of 10% iodine is used.
\n" ); document.write( "100-50=50 ml. of 40% iodine is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".10*50+.40*50=.25*100
\n" ); document.write( "5+20=25
\n" ); document.write( "25=25\r
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