document.write( "Question 504358: If a bus leaves @ 11:45 and travels at 30 mph and then a car leaves at 12:00 and travels @ 45mph when will they meet? \n" ); document.write( "
Algebra.Com's Answer #339598 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Bus 30 mph
\n" ); document.write( "Car 45 mph
\n" ); document.write( "Bus 11:45
\n" ); document.write( "Car 12:00
\n" ); document.write( "Difference in time= 00:15 => 0.25 hours
\n" ); document.write( "Bus will have covered 7.5 miles before Car starts from station
\n" ); document.write( "catch up distance= 7.5 miles
\n" ); document.write( "catch up speed = 45 -30 mph
\n" ); document.write( "catch up speed = 15 mph
\n" ); document.write( "Catchup time = catchup distance/catch up speed
\n" ); document.write( "catch up time= 7.5 / 15
\n" ); document.write( "catch up time= 0.5 hours
\n" ); document.write( "They will meet at 12:30
\n" ); document.write( "
\n" ); document.write( "
\n" );