document.write( "Question 504358: If a bus leaves @ 11:45 and travels at 30 mph and then a car leaves at 12:00 and travels @ 45mph when will they meet? \n" ); document.write( "
Algebra.Com's Answer #339598 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Bus 30 mph \n" ); document.write( "Car 45 mph \n" ); document.write( "Bus 11:45 \n" ); document.write( "Car 12:00 \n" ); document.write( "Difference in time= 00:15 => 0.25 hours \n" ); document.write( "Bus will have covered 7.5 miles before Car starts from station \n" ); document.write( "catch up distance= 7.5 miles \n" ); document.write( "catch up speed = 45 -30 mph \n" ); document.write( "catch up speed = 15 mph \n" ); document.write( "Catchup time = catchup distance/catch up speed \n" ); document.write( "catch up time= 7.5 / 15 \n" ); document.write( "catch up time= 0.5 hours \n" ); document.write( "They will meet at 12:30 \n" ); document.write( " \n" ); document.write( " |