document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=504399>Question 504399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am very confused please help. Find three consecutive integers whose sum is -114? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339591 by </B><A HREF=/tutors/aboutme.mpl?userid=nic0le116><B>nic0le116(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nic0le116><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+(x+1)+(x+2)<BR>\n" );
document.write( "x= the first number, and since we need consecutive integers, the next number will be x+1, and the next x+2.\r<BR>\n" );
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document.write( "So set this equation=-114<BR>\n" );
document.write( "x+x+1+x+2=-114 (combine like terms)<BR>\n" );
document.write( "3x+3=-114      (subtract 3 from each side)<BR>\n" );
document.write( "3x=-117       (divide each side by 3)<BR>\n" );
document.write( "x=-39         <BR>\n" );
document.write( "(now add one to this to get our 2nd number, and 1 more to get our third)<BR>\n" );
document.write( "-39+1=-38<BR>\n" );
document.write( "-38+1=-37\r<BR>\n" );
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document.write( "Now check to make sure it works!<BR>\n" );
document.write( "-39+(-38)+(-37)=-114  CHECK!\r<BR>\n" );
document.write( "\n" );
document.write( "ANSWER=-39,-38,-37 </SPAN>\n" );
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