document.write( "Question 504380: a train leaves a station and travels north at 75 km/h. two hours later a second train leaves on a parallel track and travels north at 125km/h. how far from the station will they meet? \n" ); document.write( "
Algebra.Com's Answer #339588 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Train A 75 mph \n" ); document.write( "Train B 125 mph \n" ); document.write( "Difference in time= 04:00 => 4 hours \n" ); document.write( "Train A will have covered 300 miles before Train B starts from station \n" ); document.write( "catch up distance= 300 miles \n" ); document.write( "catch up speed = 125 -75 mph \n" ); document.write( "catch up speed = 50 mph \n" ); document.write( "Catchup time = catchup distance/catch up speed \n" ); document.write( "catch up time= 300 / 50 \n" ); document.write( "catch up time= 6 hours \n" ); document.write( " \n" ); document.write( "Train B speed = 125 mph \n" ); document.write( "Time to catch up = 6 hours \n" ); document.write( "D=Speed * time \n" ); document.write( "D= 125 * 6 \n" ); document.write( "D= 750 miles \n" ); document.write( "Train B will catch up when it has traveled 750 miles \n" ); document.write( " \n" ); document.write( " |