document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=504393>Question 504393</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this i am confused. The sum of 6 and twice a number is equal to 7 less than a number. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339582 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339582\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let number be x<BR>\n" );
document.write( "2x+6 ( 6 plus twice the number)\r<BR>\n" );
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document.write( "x-7 = (7 less than the number)\r<BR>\n" );
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document.write( "2x+6=x-7<BR>\n" );
document.write( "2x-x=-7-6<BR>\n" );
document.write( "x=-13\r<BR>\n" );
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document.write( " </SPAN>\n" );
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