document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=504284>Question 504284</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fran is riding her bike on a 30 mile route. First she rides at a rate of 15 miles per hour. Then she rides at a rate of 6 miles per hour. Her total time is 2.5 hours. Find her distance ridden at 15 miles per hour and her distance ridden at 6 miles per hour </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339556 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let her ride x miles @ 15mph<BR>\n" );
document.write( "then she will ride 30-x @ 6mph<BR>\n" );
document.write( "...\r<BR>\n" );
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document.write( "Time at 15 mph + time at 6 mph = total time<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "x/15 + (30-x)/6 = 2.5\r<BR>\n" );
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document.write( "LCD =30, Multiply by LCD\r<BR>\n" );
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document.write( "2x+5(30-x)=2.5*30<BR>\n" );
document.write( "2x+150-5x=75<BR>\n" );
document.write( "-3x=-75<BR>\n" );
document.write( "x=25 \r<BR>\n" );
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document.write( "25 miles @15 mph<BR>\n" );
document.write( "5 miles @6 mph </SPAN>\n" );
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