document.write( "Question 504114: A supplement of an angle is six more than three times the angle's complement. Write an equation to represent the problem and solve for the angle, its complement, and its supplement.
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Algebra.Com's Answer #339545 by ankor@dixie-net.com(22740)\"\" \"About 
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A supplement of an angle is six more than three times the angle's complement. Write an equation to represent the problem and solve for the angle, its complement, and its supplement.
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\n" ); document.write( "Let x = the angle
\n" ); document.write( "then
\n" ); document.write( "(180-x) = it's supplement
\n" ); document.write( "and
\n" ); document.write( "(90-x) = it's complement
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\n" ); document.write( "The equation for the given statement:
\n" ); document.write( "(180-x) = 3(90-x) + 6
\n" ); document.write( "180 - x = 270 - 3x + 6
\n" ); document.write( "-x + 3x = 276 - 180
\n" ); document.write( "2x = 96
\n" ); document.write( "x = 96/2
\n" ); document.write( "x = 48 degrees is the angle
\n" ); document.write( "then
\n" ); document.write( "180 - 48 = 132 degrees is the supplement
\n" ); document.write( "and
\n" ); document.write( "90 - 48 = 42 degrees is the complement
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\n" ); document.write( "Check our solutions in the given statement:
\n" ); document.write( "\"A supplement of an angle is six more than three times the angle's complement.\"
\n" ); document.write( "132 = 3(42) + 6
\n" ); document.write( "132 = 126 + 6; confirms our solutions \n" ); document.write( "
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