document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=504121>Question 504121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the dimentions of a rectangle that has a perimeter 42 in. and an area of 104 sq in. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339512 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = perimeter<BR>\n" );
document.write( "P = 2(L+W)<BR>\n" );
document.write( "P = 42 in.<BR>\n" );
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document.write( "A = area<BR>\n" );
document.write( "A = L*W<BR>\n" );
document.write( "A = 104 sq. in.<BR>\n" );
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document.write( "L*W = 104<BR>\n" );
document.write( "L = 104/W<BR>\n" );
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document.write( "substitute<BR>\n" );
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document.write( "2(104/W + W) = 42<BR>\n" );
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document.write( "divide both sides by 2<BR>\n" );
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document.write( "104/W + W = 21<BR>\n" );
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document.write( "multiply both sides by W to eliminate fraction<BR>\n" );
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document.write( "W(104/W + W) = 21W<BR>\n" );
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document.write( "104 + W^2 = 21W<BR>\n" );
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document.write( "subtract 21W from both sides<BR>\n" );
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document.write( "104 + W^2 -21W = 0<BR>\n" );
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document.write( "rearrange<BR>\n" );
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document.write( "W^2 -21W + 104 = 0<BR>\n" );
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document.write( "factor, if possible<BR>\n" );
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document.write( "(W -8)(W -13) = 0<BR>\n" );
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document.write( "Check with FOIL<BR>\n" );
document.write( "W^2 -13W -8W + 104<BR>\n" );
document.write( "OK<BR>\n" );
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document.write( "W = 8 or -13.<BR>\n" );
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document.write( "But a negative width is nonsense.<BR>\n" );
document.write( "So, our only solution is W = 8.<BR>\n" );
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document.write( "Substitute W=8 to find L.<BR>\n" );
document.write( "L*W = 104<BR>\n" );
document.write( "L*8 = 104<BR>\n" );
document.write( "L = 13<BR>\n" );
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document.write( "Check your work using the perimeter.<BR>\n" );
document.write( "2(L+W) = 42 ?<BR>\n" );
document.write( "2(8+13) = 2(21) = 42<BR>\n" );
document.write( "Correct.<BR>\n" );
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document.write( "Answer:  The dimensions of the rectangle are 8 in. and 13 in.<BR>\n" );
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document.write( "Done.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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