document.write( "Question 504093: This one is stumping me.. I can't figure out how it comes out to be 16 and 32. Can someone show me the steps to get there? Thank you.\r
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document.write( "Jack is twice as old as Lacy. In 3 years the sum of the ages will be 54. How old are they now? \n" );
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Algebra.Com's Answer #339506 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! J = Jack's current age \n" ); document.write( "L = Lacey's current age \n" ); document.write( ". \n" ); document.write( "Jack is twice as old as Lacey. \n" ); document.write( "J = 2L \n" ); document.write( ". \n" ); document.write( "In three years... \n" ); document.write( "Jack will be J+3 years old, and \n" ); document.write( "Lacey will be L+3 years old \n" ); document.write( ". \n" ); document.write( "...the sum of their ages will be 54. \n" ); document.write( "(J+3)+(L+3) = 54 \n" ); document.write( ". \n" ); document.write( "collect and simplify \n" ); document.write( ". \n" ); document.write( "J + L + 6 = 54 \n" ); document.write( "J + L = 48 (which is the sum of their current ages) \n" ); document.write( "so, \n" ); document.write( "J = 48-L \n" ); document.write( ". \n" ); document.write( "We know equals are equal, so we can substitute: \n" ); document.write( "L = L, so \n" ); document.write( "2L = 48-L \n" ); document.write( "3L = 48 \n" ); document.write( "L = 16 \n" ); document.write( ". \n" ); document.write( "Use that to find J. \n" ); document.write( "J = 2L \n" ); document.write( "J = 32 \n" ); document.write( ". \n" ); document.write( "Check using the other facts given. \n" ); document.write( "J+3 = 35 \n" ); document.write( "L+3 = 19 \n" ); document.write( "35 + 19 = 54 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: Jack is 32, and Lacey is 16. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |