document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=504040>Question 504040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given f(x)=-2x^2 + x-5, find f(x+3). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339499 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = -2x^2 + x-5\r<BR>\n" );
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document.write( "f(x) = -2x^2 + 1x-5\r<BR>\n" );
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document.write( "f(x+3) = -2(x+3)^2 + 1(x+3)-5\r<BR>\n" );
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document.write( "f(x+3) = -2(x^2+6x+9) + 1(x+3)-5\r<BR>\n" );
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document.write( "f(x+3) = -2(x^2) - 2(6x) - 2(9) + 1(x) + 1(3) - 5\r<BR>\n" );
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document.write( "f(x+3) = -2x^2 - 12x - 18 + x + 3 - 5\r<BR>\n" );
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document.write( "f(x+3) = -2x^2 - 11x - 20\r<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "Jim  </SPAN>\n" );
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