document.write( "Question 503852: Find the number of degrees in an angle that measures 10 degrees more than its supplement \n" ); document.write( "
Algebra.Com's Answer #339430 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Supplementary Angles add up to \"180\"°.\r
\n" ); document.write( "\n" ); document.write( "let angles be \"alpha\" and \"beta\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=180\"°.........1\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"alpha\" measures \"10\" degrees more than \"beta\"; so,\r
\n" ); document.write( "\n" ); document.write( "\"alpha=beta%2B10\"....substitute in 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"beta%2B10%2Bbeta=180\"°....find \"beta\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2beta=180-10\"°\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2beta=170\"°\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"beta=170%2F2\"°\r
\n" ); document.write( "\n" ); document.write( "\"beta=85\"°\r
\n" ); document.write( "\n" ); document.write( "now find \"alpha\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"alpha=beta%2B10\"°\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"alpha=85%2B10\"°\r
\n" ); document.write( "\n" ); document.write( "\"alpha=95\"°\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );