document.write( "Question 503738: 2 men and 5 boys can do piece of work in 4 days , while 4 men and 4 boys can do in 3 day. how long would it take one man alone to do it and how many days would it take one boy alone to do it
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Algebra.Com's Answer #339413 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! 2 men and 5 boys can do piece of work in 4 days , while 4 men and 4 boys can do in 3 day. how long would it take one man alone to do it and how many days would it take one boy alone to do it. \n" ); document.write( " \r\n" ); document.write( "Make this chart:\r\n" ); document.write( "\r\n" ); document.write( " Number of Time \r\n" ); document.write( " jobs done required Rate\r\n" ); document.write( " or fraction in in\r\n" ); document.write( " thereof days jobs/day\r\n" ); document.write( "1 Man \r\n" ); document.write( "1 Boy \r\n" ); document.write( "2 Men \r\n" ); document.write( "5 Boys \r\n" ); document.write( "4 Men \r\n" ); document.write( "4 Boys \r\n" ); document.write( "2 Men and 5 Boys \r\n" ); document.write( "4 Men and 4 Boys \r\n" ); document.write( "\r\n" ); document.write( "Fill in 1 for the number of jobs done in each case:\r\n" ); document.write( "\r\n" ); document.write( " Number of Time\r\n" ); document.write( " jobs done required Rate\r\n" ); document.write( " or fraction in in\r\n" ); document.write( " thereof days jobs/day\r\n" ); document.write( "1 Man 1 \r\n" ); document.write( "1 Boy 1 \r\n" ); document.write( "2 Men 1 \r\n" ); document.write( "5 Boys 1 \r\n" ); document.write( "4 Men 1 \r\n" ); document.write( "4 Boys 1 \r\n" ); document.write( "2 Men and 5 Boys 1 \r\n" ); document.write( "4 Men and 4 Boys 1 \r\n" ); document.write( "\r\n" ); document.write( "Let M be the time required for 1 man to complete the job\r\n" ); document.write( "Let B be the time required for 1 boy to complete the job\r\n" ); document.write( "Therefore the number of days required for 2 Men will by\r\n" ); document.write( "only half of M that or M/2\r\n" ); document.write( "And the number of days required for 5 boys will be only\r\n" ); document.write( "one-fifth of B or B/5\r\n" ); document.write( "We are given the times in the last two cases.\r\n" ); document.write( "Fill all those in:\r\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " Number of Time\r\n" ); document.write( " jobs done required Rate\r\n" ); document.write( " or fraction in in\r\n" ); document.write( " thereof days jobs/day\r\n" ); document.write( "1 Man 1 M \r\n" ); document.write( "1 Boy 1 B \r\n" ); document.write( "2 Men 1 M/2 \r\n" ); document.write( "5 Boys 1 B/5 \r\n" ); document.write( "4 Men 1 M/4 \r\n" ); document.write( "4 Boys 1 B/4 \r\n" ); document.write( "2 Men and 5 Boys 1 4 \r\n" ); document.write( "4 Men and 4 Boys 1 3 \r\n" ); document.write( "\r\n" ); document.write( "Next we fill in the Rates in jobs/day by dividing\r\n" ); document.write( "number of jobs by the number of days. Notice that\r\n" ); document.write( "1 over a fraction is the reciprocal of that fraction:\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " jobs done required Rate\r\n" ); document.write( " or fraction in in\r\n" ); document.write( " thereof days jobs/day\r\n" ); document.write( "1 Man 1 M 1/M\r\n" ); document.write( "1 Boy 1 B 1/B \r\n" ); document.write( "2 Men 1 M/2 2/M \r\n" ); document.write( "5 Boys 1 B/5 5/B \r\n" ); document.write( "4 Men 1 M/4 4/M \r\n" ); document.write( "4 Boys 1 B/4 4/B\r\n" ); document.write( "2 Men and 5 Boys 1 4 1/4\r\n" ); document.write( "4 Men and 4 Boys 1 3 1/3\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The sum of the rates for 2 Men and 5 Boys must equal to their \r\n" ); document.write( "combined rate, so\r\n" ); document.write( "\r\n" ); document.write( "2/M + 5/B = 1/4\r\n" ); document.write( "\r\n" ); document.write( "The sum of the rates for 4 Men and 4 Boys must equal to their \r\n" ); document.write( "combined rate, so\r\n" ); document.write( "\r\n" ); document.write( "4/M + 4/B = 1/3\r\n" ); document.write( "\r\n" ); document.write( "So we have this system of equations:\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |