document.write( "Question 503719: Hi Guys,\r
\n" ); document.write( "\n" ); document.write( "2d/3+2d/4=2\r
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Algebra.Com's Answer #339380 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2d%2F3%2B2d%2F4=2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"12%282d%2Fcross%283%29%2B2d%2Fcross%284%29%29=12%282%29\" Multiply both sides by the LCD \"12\" to clear any fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"8d%2B6d=24\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"14d=24\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"d=%2824%29%2F%2814%29\" Divide both sides by \"14\" to isolate \"d\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=12%2F7\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"d=12%2F7\" \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, feel free to email me at jim_thompson5910@hotmail.com
\n" ); document.write( "or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html\r
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\n" ); document.write( "\n" ); document.write( "Jim
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