document.write( "Question 503698: A student weighs 885 pennies and finds them to have a mass of 2500.4g. If the pre-1982 pennies weigh an average 3.09g and the post-1982 pennies weigh 2.51 g. How many of pennies are pre-1982 \n" ); document.write( "
Algebra.Com's Answer #339370 by oberobic(2304)\"\" \"About 
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X = count of old pennies
\n" ); document.write( "3.09*X = weight of old pennies
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\n" ); document.write( "Y = count of new pennies
\n" ); document.write( "2.51*Y = weight of new pennies
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\n" ); document.write( "X+Y = 885 pennies
\n" ); document.write( "Y = 885-X
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\n" ); document.write( "3.09*X + 2.51*Y = 2500.4
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\n" ); document.write( "multiply by 100 to remove decimals
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\n" ); document.write( "309X + 251Y = 250040
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\n" ); document.write( "substitute for Y = 885-X
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\n" ); document.write( "309X + 251(885-X) = 250040
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\n" ); document.write( "309X + 222135 -251X = 250040
\n" ); document.write( "309X -251X = 250040 - 222135
\n" ); document.write( "58X = 27905
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\n" ); document.write( "X = 481.12
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\n" ); document.write( "Recall, we do not have counts but instead have average weights.
\n" ); document.write( "So having a result that is not an integer is to be expected.
\n" ); document.write( "We can assume X = 481.
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\n" ); document.write( "That means
\n" ); document.write( "Y = 885 - 481
\n" ); document.write( "Y = 404
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\n" ); document.write( "Always check your work.
\n" ); document.write( "3.09 * 481 = 1486.29
\n" ); document.write( "2.51 * 404 = 1014.04
\n" ); document.write( "1486.29+1014.04 = 2500.33
\n" ); document.write( "Compared to 2500.4, it's close.
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\n" ); document.write( "Answer: There were 481 older pennies and 404 newer pennies.
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