document.write( "Question 503671: At the north campus of a college, 10% of students are music majors. At the south campus 90% of the students are music majors. Both campuses are merged into one east campus. If 42%of the 1000 students are music majors, how many students did each of the north and south campuses have before the merger. \r
\n" ); document.write( "\n" ); document.write( "I tried 42%of 1000 = 420 but can't figure how to get the number of students. Help!
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Algebra.Com's Answer #339350 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
m = percentage of music majors
\n" ); document.write( "s = total students in south campus
\n" ); document.write( "n = total students on north campus
\n" ); document.write( "s+n = 1000
\n" ); document.write( ".
\n" ); document.write( "so
\n" ); document.write( "n = 1000-s
\n" ); document.write( "s = 1000-n
\n" ); document.write( ".
\n" ); document.write( ".10n = number of music majors on north campus
\n" ); document.write( ".90s = number of students in south campus
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\n" ); document.write( "420 of 1000 total students are music majors
\n" ); document.write( ".
\n" ); document.write( ".1n + .9s = 420
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\n" ); document.write( "substitute for s = 1000-n
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\n" ); document.write( ".1n + .9(1000-n) = 420
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\n" ); document.write( "multiply by 10 to remove decimals
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\n" ); document.write( "n + 9(1000-n) = 4200
\n" ); document.write( "n + 9000 -9n = 4200
\n" ); document.write( "-8n = -4800
\n" ); document.write( "n = 600
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\n" ); document.write( "s = 1000-s
\n" ); document.write( "s = 400
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\n" ); document.write( "Always check your work.
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\n" ); document.write( ".10n = .1(600) = 60
\n" ); document.write( ".90s = .9(400) = 360
\n" ); document.write( "60+360 = 420
\n" ); document.write( "Correct.
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\n" ); document.write( "Re-read the question to make sure you answer it.
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\n" ); document.write( "Answer: the north campus had 600 students, and the south campus had 400 students.
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\n" ); document.write( "Done.\r
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