document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=503639>Question 503639</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangular lake-front lot has a perimeter of 1900 feet. One side is 200 feet longer than the shortest side, while the third side is 500 feet longer than the shortest side. Find the lengths of all three sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339330 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = perimeter = sum of the sides<BR>\n" );
document.write( "a = shortest side<BR>\n" );
document.write( "b = a+200<BR>\n" );
document.write( "c = a+500<BR>\n" );
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document.write( "a+b+c = 1900<BR>\n" );
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document.write( "substitute<BR>\n" );
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document.write( "a +a+200 +a+500 = 1900<BR>\n" );
document.write( "3a +700 = 1900<BR>\n" );
document.write( "3a = 1200<BR>\n" );
document.write( "a = 400<BR>\n" );
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document.write( "b = 400+200 <BR>\n" );
document.write( "b = 600<BR>\n" );
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document.write( "c = 400+500<BR>\n" );
document.write( "c = 900<BR>\n" );
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document.write( "The three sides of the traingle are:<BR>\n" );
document.write( "400 ft<BR>\n" );
document.write( "600 ft<BR>\n" );
document.write( "900 ft<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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