document.write( "Question 503566: mike rented a car for five days and drove 300 miles. he was charged $300.00. tim rented the same car for six days and drove 220 miles. he was charged $325.00. what does the company charge per day and per mile. \n" ); document.write( "

Algebra.Com's Answer #339322 by oberobic(2304) $\"\"$ $\"About$

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d = charge per day in dollars
\n" ); document.write( "m = charge per mile in dollars
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\n" ); document.write( "5d + 300m = 300
\n" ); document.write( "6d + 220m = 325
\n" ); document.write( ".
\n" ); document.write( "multiply the first equation by 6 and the second by 5, then subtract
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\n" ); document.write( "30d + 1800m = 1800
\n" ); document.write( "30d + 1100m = 1625
\n" ); document.write( "--------------------
\n" ); document.write( "700m = 175
\n" ); document.write( "m = 175/700
\n" ); document.write( "m = 1/4 of $1 per mile
\n" ); document.write( "m = 25 cents per mile
\n" ); document.write( ".
\n" ); document.write( "substitute into first equation to find d.
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\n" ); document.write( "5d + 300(1/4) = 300
\n" ); document.write( "5d + 75 = 300
\n" ); document.write( "5d = 225
\n" ); document.write( "d = 45
\n" ); document.write( "d = $45 dollars per day
\n" ); document.write( ".
\n" ); document.write( "Always check your work.
\n" ); document.write( "in this case, use the 2nd equation.
\n" ); document.write( "6d + 220m = 325
\n" ); document.write( ".
\n" ); document.write( "6d = 6(45) = 270
\n" ); document.write( "220m = 220*1/4 = 55
\n" ); document.write( "270+55 = 325
\n" ); document.write( "Correct.
\n" ); document.write( ".
\n" ); document.write( "Answer: The car rental company charge $45 per day plus $0.25 (25 cents) per mile.
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\n" ); document.write( "Note that is is important to keep the units of measurement the same.
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\n" ); document.write( "Done.
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