document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=503607>Question 503607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of the indicated angles complementary angles with measures\r<BR>\n" );
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document.write( "A. 4x-9  B. 6x-1\r<BR>\n" );
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document.write( "Please describe how you solved the above problem. I am trying to learn how to solve this type of problem. I have been unsuccessful searching online. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339321 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the measure of the indicated angles complementary angles with measures <BR>\n" );
document.write( "A. 4x-9 B. 6x-1 <BR>\n" );
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document.write( "let A= one of the complementary angles=4x-9<BR>\n" );
document.write( "let B=the other complementary angle=6x-1<BR>\n" );
document.write( "The sum of complementary angles=90º<BR>\n" );
document.write( "A+B=90º<BR>\n" );
document.write( "4x-9+6x-1=90<BR>\n" );
document.write( "10x-10=90<BR>\n" );
document.write( "10x=90+10=100<BR>\n" );
document.write( "x=10º<BR>\n" );
document.write( "complementary angle=90-10=80º<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "The two compementary angles are: 10º and 80º </SPAN>\n" );
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