document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=503595>Question 503595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. The measure of one angle is twice as large as the measure of the other. Find the number of degrees in each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339309 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. The measure of one angle is twice as large as the measure of the other. Find the number of degrees in each angle.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=one angle<BR>\n" );
document.write( "180-x=angle's supplement<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x=2(180-x)<BR>\n" );
document.write( "x=360-2x<BR>\n" );
document.write( "3x=360<BR>\n" );
document.write( "x=120º<BR>\n" );
document.write( "180-x=180-120=60º<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "The two angles are 120º and 60º </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );