document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6312>Question 6312</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem Solving Using Systems of Equations\r<BR>\n" );
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document.write( "Julie and Eric row their boat(at a constant speed) 55 miles downstream for 5 hours, helped by the current. Rowing at the same rate, the trip back against the current takes 11 hours.  Find the rate of the current </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3393 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Assume the rowing speed is Vr and the current speed is Vw.<BR>\n" );
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document.write( " We have the downstream speed: Vr + Vw = 55/5 = 11 ...(1) <BR>\n" );
document.write( " and the upstream speed    Vr - Vw = 55/11 = 5 ...(2)\r<BR>\n" );
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document.write( " Hence, Vr = (11+5)/2 = 8 miles/hr and Vw = (11-5)/2 = 3 miles/hr\r<BR>\n" );
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document.write( " Kenny<BR>\n" );
document.write( " PS: Usually, I don't answer such kind of simple question and similar<BR>\n" );
document.write( "     questions appeared thousand times here.<BR>\n" );
document.write( "     To avoid that you got terrible long solutions so I showed something<BR>\n" );
document.write( "     that I learned when I was in elementary school and hope you don't <BR>\n" );
document.write( "     bother with this kinds of question any more. </SPAN>\n" );
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