document.write( "Question 503514: What is the value of (1+1/2)(1+1/3)(1+1/4)...(1+1/2011)? choose the answer and explain the reason to choose your response
\n" ); document.write( " 1005
\n" ); document.write( "2011
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\n" ); document.write( " 2012
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Algebra.Com's Answer #339281 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
(1+1/2)(1+1/3)(1+1/4)(1+1/5)(1+1/6)...(1+1/2011)\r
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\n" ); document.write( "\n" ); document.write( "(2/2+1/2)(3/3+1/3)(4/4+1/4)(5/5+1/5)(6/6+1/6)...(2011/2011+1/2011)\r
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\n" ); document.write( "\n" ); document.write( "(3/2)(4/3)(5/4)(6/5)(7/6)...(2012/2011)\r
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\n" ); document.write( "\n" ); document.write( "Notice in the last step, there's a 3 in the first numerator and a 3 in the second denominator. These terms will cancel. Also, there's a 4 in the second numerator and a 4 in the third denominator. These terms will cancel too. The basic pattern is that any given numerator will cancel with the the denominator in the next fraction\r
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\n" ); document.write( "\n" ); document.write( "All this cancelling leaves us with \r
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\n" ); document.write( "\n" ); document.write( "(1/2)(1/1)(1/1)(1/1)(1/1)...(2012/1)\r
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\n" ); document.write( "\n" ); document.write( "which collapses to (1/2)(2012/1) and that multiplies and simplifies to 2012/2 = 1006\r
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\n" ); document.write( "\n" ); document.write( "So the answer is choice C\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, feel free to email me at jim_thompson5910@hotmail.com
\n" ); document.write( "or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html\r
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\n" ); document.write( "\n" ); document.write( "Thanks,\r
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\n" ); document.write( "\n" ); document.write( "Jim
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