document.write( "Question 503361: The sum of present ages of Ian and his brother is 45. In 5 years, Ian will be 5/6 of his brother's age. Find their present ages. \n" ); document.write( "

Algebra.Com's Answer #339234 by ptaylor(2198) $\"\"$ $\"About$

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Let x=Ian's age
\n" ); document.write( "And let y=his brother's age\r
\n" ); document.write( "\n" ); document.write( "x+y=45----------------------eq1
\n" ); document.write( "and
\n" ); document.write( "x+5=(5/6)(y+5) multiply each term by 6
\n" ); document.write( "6x+30=5(y+5) or
\n" ); document.write( "6x+30=5y+25 subtract 5y and also 30 from each side
\n" ); document.write( "6x-5y=-5----------------eq2\r
\n" ); document.write( "\n" ); document.write( "multiply eq1 by 5 and add it to eq2 and we get:
\n" ); document.write( "11x=220
\n" ); document.write( "x=20-------------Ian's age
\n" ); document.write( "from eq1, 20+y=45
\n" ); document.write( "y=25 -----------brother's age\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "20+25=45
\n" ); document.write( "45=45
\n" ); document.write( "and
\n" ); document.write( "20+5=(5/6)(25+5)
\n" ); document.write( "25=25
\n" ); document.write( "Hope this helps-----ptaylor \n" ); document.write( "

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