document.write( "Question 50901: 3xy+y=15\r
\n" ); document.write( "\n" ); document.write( "I tried dividing by 3, thus leaving xy+y=2, but there's where I get stuck. I need help on how to solve this please! A soon response would be greatly appreciated.
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Algebra.Com's Answer #33923 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3xy+y=15
\n" ); document.write( "y(3x+1)=15
\n" ); document.write( "y=15/(3x+1)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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