document.write( "Question 50901: 3xy+y=15\r
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document.write( "I tried dividing by 3, thus leaving xy+y=2, but there's where I get stuck. I need help on how to solve this please! A soon response would be greatly appreciated. \n" );
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Algebra.Com's Answer #33923 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3xy+y=15 \n" ); document.write( "y(3x+1)=15 \n" ); document.write( "y=15/(3x+1)\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |