document.write( "Question 503419: What is the slope of this tangent if given this point?\r
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document.write( "y=4/x (-2,8)\r
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document.write( "It reads: y equals four over x
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document.write( "The given point is: (-2, 8)\r
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document.write( "An explanation as to how the answer was reached would be wonderful! :) \n" );
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Algebra.Com's Answer #339229 by oberobic(2304) ![]() You can put this solution on YOUR website! Looking at the graph, you can see that y = 4/x is not truly a linear equation. \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Actually \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The point (-2,8) is not on the curve, which you see above. Or prove it by plugging the x value into the equation: \n" ); document.write( "y = 4/x \n" ); document.write( "x = -2 \n" ); document.write( "y = -2, not 8\r \n" ); document.write( "\n" ); document.write( "That creates another problem for you. \n" ); document.write( ". \n" ); document.write( "In general the slope of a line tangent to a curve can be found using the first derivative. \n" ); document.write( "But that is a calculus question, not algebra. \n" ); document.write( ". \n" ); document.write( "The first derivative of \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That is the slope of the line tangent to the curve for any value of 'x'. \n" ); document.write( "But you need a point on the curve, which you do not have. \n" ); document.write( "So, there is something wrong with your problem statement. \n" ); document.write( ". \n" ); document.write( "But assuming the point = (-2,-2) \n" ); document.write( "The slope is: \n" ); document.write( "-4/(-2^2) = -4/4 = -1 at that point. \n" ); document.write( ". \n" ); document.write( "Remember this is a curve, so the slope changes continuously. \n" ); document.write( "(except there is a discontinuity at x=0 because 4/0 is undefined) \n" ); document.write( ". \n" ); document.write( "Substituting in the slope-intercept equation: \n" ); document.write( "y = mx+b\r \n" ); document.write( "\n" ); document.write( "-2 = -1*(-2) + b \n" ); document.write( "b = -4 \n" ); document.write( ". \n" ); document.write( "y = -x -4 \n" ); document.write( "which is a linear equation. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Of course, you could have picked another point. \n" ); document.write( "Let's say x =4 \n" ); document.write( "The curve is y = x/4, so y=1. \n" ); document.write( "(4,1) \n" ); document.write( ". \n" ); document.write( "m = -4/(4^2) = -4/16 = -1/4 \n" ); document.write( ". \n" ); document.write( "1 = -1/4(4) + b \n" ); document.write( ". \n" ); document.write( "so \n" ); document.write( "b=2 \n" ); document.write( ". \n" ); document.write( "y = (-1/4)x+2 \n" ); document.write( "which is a linear equation tangent to the curve at (4,1)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |