document.write( "Question 503419: What is the slope of this tangent if given this point?\r
\n" ); document.write( "\n" ); document.write( "y=4/x (-2,8)\r
\n" ); document.write( "\n" ); document.write( "It reads: y equals four over x
\n" ); document.write( "The given point is: (-2, 8)\r
\n" ); document.write( "\n" ); document.write( "An explanation as to how the answer was reached would be wonderful! :)
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Algebra.Com's Answer #339229 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
Looking at the graph, you can see that y = 4/x is not truly a linear equation.
\n" ); document.write( "\"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C4%2Fx%29\"
\n" ); document.write( ".
\n" ); document.write( "Actually
\n" ); document.write( "\"y+=+4+%2A+x%5E%28-1%29\"
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\n" ); document.write( "The point (-2,8) is not on the curve, which you see above. Or prove it by plugging the x value into the equation:
\n" ); document.write( "y = 4/x
\n" ); document.write( "x = -2
\n" ); document.write( "y = -2, not 8\r
\n" ); document.write( "\n" ); document.write( "That creates another problem for you.
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\n" ); document.write( "In general the slope of a line tangent to a curve can be found using the first derivative.
\n" ); document.write( "But that is a calculus question, not algebra.
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\n" ); document.write( "The first derivative of
\n" ); document.write( "\"4%2Fx+=+-4%2Fx%5E2\"
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\n" ); document.write( "That is the slope of the line tangent to the curve for any value of 'x'.
\n" ); document.write( "But you need a point on the curve, which you do not have.
\n" ); document.write( "So, there is something wrong with your problem statement.
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\n" ); document.write( "But assuming the point = (-2,-2)
\n" ); document.write( "The slope is:
\n" ); document.write( "-4/(-2^2) = -4/4 = -1 at that point.
\n" ); document.write( ".
\n" ); document.write( "Remember this is a curve, so the slope changes continuously.
\n" ); document.write( "(except there is a discontinuity at x=0 because 4/0 is undefined)
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\n" ); document.write( "Substituting in the slope-intercept equation:
\n" ); document.write( "y = mx+b\r
\n" ); document.write( "\n" ); document.write( "-2 = -1*(-2) + b
\n" ); document.write( "b = -4
\n" ); document.write( ".
\n" ); document.write( "y = -x -4
\n" ); document.write( "which is a linear equation.
\n" ); document.write( ".
\n" ); document.write( "\"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C4%2Fx%2C-x-4%29\"
\n" ); document.write( ".
\n" ); document.write( "Of course, you could have picked another point.
\n" ); document.write( "Let's say x =4
\n" ); document.write( "The curve is y = x/4, so y=1.
\n" ); document.write( "(4,1)
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\n" ); document.write( "m = -4/(4^2) = -4/16 = -1/4
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\n" ); document.write( "1 = -1/4(4) + b
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\n" ); document.write( "so
\n" ); document.write( "b=2
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\n" ); document.write( "y = (-1/4)x+2
\n" ); document.write( "which is a linear equation tangent to the curve at (4,1)\r
\n" ); document.write( "\n" ); document.write( "\"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C4%2Fx%2C-x-4%2C-1%2F4%2Ax%2B2%29\"
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