document.write( "Question 503327: In the length of the right angle,find the length of the side not given.Give an exact answer and approximation to three decimal places. a=15,b=15 \n" ); document.write( "
Algebra.Com's Answer #339191 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "We basically have this triangle set up:\r
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\n" ); document.write( "\n" ); document.write( "To find the unknown length, we need to use the Pythagorean Theorem.\r
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\n" ); document.write( "\n" ); document.write( "Remember, the Pythagorean Theorem is \"a%5E2%2Bb%5E2=c%5E2\" where \"a\" and \"b\" are the legs of a triangle and \"c\" is the hypotenuse.\r
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\n" ); document.write( "\n" ); document.write( "Since the legs are \"15\" and \"15\" this means that \"a=15\" and \"b=15\"\r
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\n" ); document.write( "\n" ); document.write( "Also, since the hypotenuse is \"x\", this means that \"c=x\".\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" Start with the Pythagorean theorem.\r
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\n" ); document.write( "\n" ); document.write( "\"15%5E2%2B15%5E2=x%5E2\" Plug in \"a=15\", \"b=15\", \"c=x\" \r
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\n" ); document.write( "\n" ); document.write( "\"225%2B15%5E2=x%5E2\" Square \"15\" to get \"225\".\r
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\n" ); document.write( "\n" ); document.write( "\"225%2B225=x%5E2\" Square \"15\" to get \"225\".\r
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\n" ); document.write( "\n" ); document.write( "\"450=x%5E2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=450\" Rearrange the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%28450%29\" Take the square root of both sides. Note: only the positive square root is considered (since a negative length doesn't make sense).\r
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\n" ); document.write( "\n" ); document.write( "\"x=15%2Asqrt%282%29\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=15%2Asqrt%282%29\" which approximates to \"x=21.213\".
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