document.write( "Question 503214: A random variable X has mean 110 and standard deviation 18, and a random variable Y has mean 215 and standard deviation 30; and the correlation between X and Y is r=0.75. The standard deviation of X+Y is [x]. (Round your answer to 2 decimal places.) \n" ); document.write( "
Algebra.Com's Answer #339141 by Sarpi(32) You can put this solution on YOUR website! E(.)= the mean \n" ); document.write( "s(.)= the standard deviation\r \n" ); document.write( "\n" ); document.write( "So, E(X)=110 s(X)=18 ; E(Y)=215 s(Y)=30 \n" ); document.write( " r(X,Y)=0.75 \n" ); document.write( "The standard deviation of X+Y, formula; \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The above formula comes from this general formula \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Formula: \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Cov(x,y)=405\r \n" ); document.write( "\n" ); document.write( "However, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That implies \n" ); document.write( "So, s(X+Y)=45.10\r \n" ); document.write( "\n" ); document.write( "I hope you really understand the steps. And your feedback will be appreciated. \n" ); document.write( " |