document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=503132>Question 503132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.a father is now 5 times as old as his son. 21 years hence he will be twice as old as his son . what are their ages.\r<BR>\n" );
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document.write( "2.find a number such that when 58 is added to it , the result is equal to 3 x the number.\r<BR>\n" );
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document.write( "3.in 8 year time time mart age will be 4 times her age 7 years ago. if Mary is x year now. what is Marys age in 8 year time .<BR>\n" );
document.write( "Marys age 7 years ago <BR>\n" );
document.write( "solve x  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339092 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Q1.<BR>\n" );
document.write( "A father is now 5 times as old as his son. 21 years hence he will be twice as old as his son . what are their ages. \r<BR>\n" );
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document.write( "Let <BR>\n" );
document.write( "present age of father = f<BR>\n" );
document.write( "present age of son = s\r<BR>\n" );
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document.write( "Father is 5 times as old as son<BR>\n" );
document.write( "f=5s ..............(1)<BR>\n" );
document.write( "After 21 years means we have to add 21 in the present ages of son and father<BR>\n" );
document.write( "f+21=s+21<BR>\n" );
document.write( "then<BR>\n" );
document.write( "father will be twice as old as his son<BR>\n" );
document.write( "f+21=2(s+21)<BR>\n" );
document.write( "f+21=2s+42<BR>\n" );
document.write( "f=2s+42-21<BR>\n" );
document.write( "f=2s+21 ...........(2)<BR>\n" );
document.write( "Put the value of from (1) to (2), we have<BR>\n" );
document.write( "f=2s+21<BR>\n" );
document.write( "5s=2s+21<BR>\n" );
document.write( "5s-2s=21<BR>\n" );
document.write( "3s=21<BR>\n" );
document.write( "s=21/3<BR>\n" );
document.write( "s=7<BR>\n" );
document.write( "Put the value of s in (1), we have<BR>\n" );
document.write( "f=5s<BR>\n" );
document.write( "f=5*7<BR>\n" );
document.write( "f=35<BR>\n" );
document.write( "present age of father = 35<BR>\n" );
document.write( "present age of son = 7\r<BR>\n" );
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document.write( "Q2.<BR>\n" );
document.write( "find a number such that when 58 is added to it , the result is equal to 3 x the number. <BR>\n" );
document.write( "Let <BR>\n" );
document.write( "Number = x<BR>\n" );
document.write( "3x=x+58<BR>\n" );
document.write( "3x-x=58<BR>\n" );
document.write( "2x=58<BR>\n" );
document.write( "x=58/2<BR>\n" );
document.write( "x=29<BR>\n" );
document.write( "Number = 29\r<BR>\n" );
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document.write( "Q3.<BR>\n" );
document.write( "In 8 year time time Mary age will be 4 times her age 7 years ago. if Mary is x year now. what is Marys age in 8 year time .<BR>\n" );
document.write( "Marys age 7 years ago <BR>\n" );
document.write( "solve x\r<BR>\n" );
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document.write( "Mary's age now = x<BR>\n" );
document.write( "7 years ago = x-7<BR>\n" );
document.write( "After 8 years time = x+8<BR>\n" );
document.write( "After 8 years from now, Mary age will be 4 times her age 7 years ago<BR>\n" );
document.write( "4(x-7)=x+8<BR>\n" );
document.write( "4x-28=x+8<BR>\n" );
document.write( "4x-x=8+28<BR>\n" );
document.write( "3x=36<BR>\n" );
document.write( "x=36/3<BR>\n" );
document.write( "x=12\r<BR>\n" );
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document.write( "Mary is 12 years old now.<BR>\n" );
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