document.write( "Question 502900:  Hello: \r
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document.write( "This one has me stumped. The probability that Student A comes to class is .99. INDEPENDENTLY, the probability that Student B comes to class is .98. The probability that NEITHER attend class is (this is what the answer is I must come up with)? Is this where an intersection would come in? P(A intersect B) Thank you for any assistance you can provide. :)
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| Algebra.Com's Answer #339054 by sudhanshu_kmr(1152)     You can put this solution on YOUR website! \n" ); document.write( "Both are independent events. \r \n" ); document.write( "\n" ); document.write( "probability that Student A doesn't attend the class = 1- 0.99 = 0.01\r \n" ); document.write( "\n" ); document.write( "probability that Student B doesn't attend the class = 1- 0.98 = 0.02\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability that neither attend class = 0.01 *0.02 = 2/10000 = 0.0002\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |