document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=499849>Question 499849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to fine the sine and cosine of angle theta in standard position who's terminal side passes through the given point (-15,-12). I also need to find the measure of angle theta to the nearest tenth of a degree. I must assume that theta is greater than or equal to 0 degrees and is less than 360 degrees.\r<BR>\n" );
document.write( "\n" );
document.write( "I got as far as finding out the hypotenuse is the square root of 369, but I don't know how to use those trig. functions to find the reference angle in order to find theta. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339051 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need to fine the sine and cosine of angle theta in standard position who's terminal side passes through the given point (-15,-12). I also need to find the measure of angle theta to the nearest tenth of a degree. I must assume that theta is greater than or equal to 0 degrees and is less than 360 degrees. <BR>\n" );
document.write( "I got as far as finding out the hypotenuse is the square root of 369, but I don't know how to use those trig. functions to find the reference angle in order to find theta.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "Quadrant III is the only quadrant where sin and cos functions are both negative. <BR>\n" );
document.write( "You are working a right triangle in quadrant III with a horizontal leg of -15 (cos), a vertical leg of -12 (sin) and a hypotenuse you correctly calculated to be=&#8730;(369). The reference angle is<BR>\n" );
document.write( "the inverse of the sin theta or cos theta.  <BR>\n" );
document.write( "sin theta=-12/&#8730;369<BR>\n" );
document.write( "cos theta=-15/&#8730;369<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Using a calculator to find reference angle:<BR>\n" );
document.write( "arccos(15/&#8730;369)=38.7º<BR>\n" );
document.write( "arcsin(12/&#8730;369)=38.7º<BR>\n" );
document.write( "Theta=38.7+180=218.7º (quadrant III) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );