document.write( "Question 502935: Maria is three times as old as her brother. In four years, Maria will be twice as old as he will be then. How old is Maria's brother now? \n" ); document.write( "
Algebra.Com's Answer #339047 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Maria = m
\n" ); document.write( "Present age of Brother = b
\n" ); document.write( "Given
\n" ); document.write( "Maria is three times as old as her brother
\n" ); document.write( "m=3b ..........(1)
\n" ); document.write( "In four years means we have to add 4 in their present ages
\n" ); document.write( "m+4=b+4
\n" ); document.write( "then Maria will be twice as old
\n" ); document.write( "m+4=2(b+4)
\n" ); document.write( "m+4=2b+8
\n" ); document.write( "m=2b+8-4
\n" ); document.write( "m=2b+4 .............(2)
\n" ); document.write( "Plug in the value of m from (1) to (2)
\n" ); document.write( "3b=2b+4
\n" ); document.write( "3b-2b=4
\n" ); document.write( "b=4\r
\n" ); document.write( "\n" ); document.write( "Brother is 4 years old\r
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