document.write( "Question 502935: Maria is three times as old as her brother. In four years, Maria will be twice as old as he will be then. How old is Maria's brother now? \n" ); document.write( "
Algebra.Com's Answer #339047 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Maria = m \n" ); document.write( "Present age of Brother = b \n" ); document.write( "Given \n" ); document.write( "Maria is three times as old as her brother \n" ); document.write( "m=3b ..........(1) \n" ); document.write( "In four years means we have to add 4 in their present ages \n" ); document.write( "m+4=b+4 \n" ); document.write( "then Maria will be twice as old \n" ); document.write( "m+4=2(b+4) \n" ); document.write( "m+4=2b+8 \n" ); document.write( "m=2b+8-4 \n" ); document.write( "m=2b+4 .............(2) \n" ); document.write( "Plug in the value of m from (1) to (2) \n" ); document.write( "3b=2b+4 \n" ); document.write( "3b-2b=4 \n" ); document.write( "b=4\r \n" ); document.write( "\n" ); document.write( "Brother is 4 years old\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |